XLPack 7.0
XLPack 数値計算ライブラリ (Excel VBA) リファレンスマニュアル
読み取り中…
検索中…
一致する文字列を見つけられません
関数
D2a4. 連立一次方程式 (一般行列) (反復法ソルバー)

関数

Sub Bicg (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.5, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 双共役勾配(BICG)法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Bicg1 (N As Long, Val() As Double, Rowptr() As Long, Colind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10)
 双共役勾配(BICG)法による連立一次方程式 Ax = b の解 (シンプルドライバ)
 
Sub Bicg_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 双共役勾配(BICG)法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Bicg_s (N As Long, Matvec As LongPtr, MatvecTrans As LongPtr, Psolve As LongPtr, PsolveTrans As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 双共役勾配(BICG)法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Cgs (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.5, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 二乗共役勾配(CGS)法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Cgs_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 二乗共役勾配(CGS)法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Cgs_s (N As Long, ByVal Matvec As LongPtr, ByVal Psolve As LongPtr, ByVal ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 二乗共役勾配(CGS)法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Diom (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional M As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.5, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 不完全直交化法(DIOM)による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Diom_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 不完全直交化法(DIOM)による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Diom_s (N As Long, Matvec As LongPtr, Psolve As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 不完全直交化法(DIOM)による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Dqgmres (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional M As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.5, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 疑似最小残差(DQGMRES)法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Dqgmres_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 疑似最小残差(DQGMRES)法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Dqgmres_s (N As Long, Matvec As LongPtr, Psolve As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 疑似最小残差(DQGMRES)法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Fgmres (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional M As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.5, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 最小残差(FGMRES)法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Fgmres_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 最小残差(FGMRES)法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Fgmres_s (N As Long, Matvec As LongPtr, Psolve As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 最小残差(FGMRES)法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Fom (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional M As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.5, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 完全直交化法(FOM)による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Fom_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 完全直交化法(FOM)による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Fom_s (N As Long, Matvec As LongPtr, Psolve As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 完全直交化法(FOM)による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Gcr (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional M As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.5, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 一般化共役残差(GCR)法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Gcr_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 一般化共役残差(GCR)法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Gcr_s (N As Long, Matvec As LongPtr, Psolve As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 一般化共役残差(GCR)法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Gpbicg (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional Mode As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.7, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 積型双共役勾配(GPBICG)法, 安定化双共役勾配(BICGSTAB)法 または BICGSTAB2法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Gpbicg_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional Mode As Long=0, Optional MaxIter As Long=500)
 積型双共役勾配(GPBICG)法, 安定化双共役勾配(BICGSTAB)法 または BICGSTAB2法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Gpbicg_s (N As Long, Matvec As LongPtr, Psolve As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Mode As Long=0, Optional MaxIter As Long=500)
 積型双共役勾配(GPBICG)法, 安定化双共役勾配(BICGSTAB)法 または BICGSTAB2法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Orthomin (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional M As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.7, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 Orthomin法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Orthomin_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 Orthomin法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Orthomin_s (N As Long, Matvec As LongPtr, Psolve As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional M As Long=0, Optional MaxIter As Long=500)
 Orthomin法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Qmr (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.5, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 疑似最小残差(QMR)法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Qmr_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 疑似最小残差(QMR)法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Qmr_s (N As Long, Matvec As LongPtr, MatvecTrans As LongPtr, Psolve As LongPtr, PsolveTrans As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 疑似最小残差(QMR)法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Sor (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional Omega As Double=1.5, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1)
 逐次的過剰緩和(SOR)法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Sor_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 逐次的過剰緩和(SOR)法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Sor_s (N As Long, Matvec As LongPtr, Matsol As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 逐次的過剰緩和(SOR)法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 
Sub Tfqmr (N As Long, Val() As Double, Ptr() As Long, Ind() As Long, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional Format As Long=0, Optional MaxIter As Long=500, Optional Tol As Double=1.0E-10, Optional Base As Long=-1, Optional Precon As Long=0, Optional Omega As Double=1.5, Optional P As Long=3, Optional Nnz2 As Long=-1, Optional Md As Long=0)
 転置不要疑似最小残差(TFQMR)法による連立一次方程式 Ax = b の解 (ドライバ)
 
Sub Tfqmr_r (N As Long, B() As Double, X() As Double, Info As Long, XX() As Double, YY() As Double, IRev As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 転置不要疑似最小残差(TFQMR)法による連立一次方程式 Ax = b の解 (リバースコミュニケーション版)
 
Sub Tfqmr_s (N As Long, Matvec As LongPtr, Psolve As LongPtr, ChkConv As LongPtr, B() As Double, X() As Double, Optional Info As Long, Optional Iter As Long, Optional Res As Double, Optional MaxIter As Long=500)
 転置不要疑似最小残差(TFQMR)法による連立一次方程式 Ax = b の解 (サブルーチン形式)
 

詳解

D2a4. 連立一次方程式 (一般行列) (反復法ソルバー) プログラムを表示しています.