{"id":3062,"date":"2019-02-26T12:00:00","date_gmt":"2019-02-26T03:00:00","guid":{"rendered":"https:\/\/www.ktech.biz\/jp\/?p=3062"},"modified":"2024-12-03T13:36:08","modified_gmt":"2024-12-03T04:36:08","slug":"xlpack-solver-quad3","status":"publish","type":"post","link":"https:\/\/www.ktech.biz\/jp\/document\/xlpack-solver-quad3\/","title":{"rendered":"XLPack \u30bd\u30eb\u30d0\u30fc \u6570\u5024\u7a4d\u5206 (\u7121\u9650\u533a\u9593)"},"content":{"rendered":"\n\u7a4d\u5206\u533a\u9593\u306e\u4e0a\u9650\u4e0b\u9650\u5171\u306b\u7121\u9650\u5927\u3059\u306a\u308f\u3061 [-\u221e, +\u221e] \u306e\u6570\u5024\u7a4d\u5206\u3092\u884c\u3044\u307e\u3059.
\n\\[
\nf(x) = \\frac{1}{1 + x^2}
\n\\]\n\u306e\u7a4d\u5206
\n\\[
\nS = \\int_{-\\infty}^{+\\infty} f(x) dx
\n\\]\n\u3092\u6c42\u3081\u308b\u4f8b\u3092\u793a\u3057\u307e\u3059.<\/p>\n

\u5909\u6570\u30bb\u30eb (\u3053\u306e\u5834\u5408 B6) \u306b\u306f\u30d7\u30ed\u30b0\u30e9\u30e0\u304c x \u306e\u5024\u3092\u66f8\u304d\u8fbc\u307f\u307e\u3059. \u95a2\u6570\u5024\u30bb\u30eb (\u3053\u306e\u5834\u5408 B7) \u306b\u306f x \u304b\u3089 f(x) \u3092\u6c42\u3081\u308b\u6570\u5f0f\u3092\u5165\u529b\u3057\u3066\u304a\u304d\u307e\u3059. \u3053\u306e\u5834\u5408, =1\/(1+B6^2) \u3068\u3057\u307e\u3059.<\/p>\n

\u7a4d\u5206\u533a\u9593\u306f\u6307\u5b9a\u3059\u308b\u5fc5\u8981\u304c\u306a\u3044\u305f\u3081\u8a08\u7b97\u5024 (\u51fa\u529b) \u306e\u305f\u3081\u306e\u30bb\u30eb (\u3053\u306e\u5834\u5408 D7) \u3060\u3051\u3092\u6307\u5b9a\u3057\u307e\u3059. \u300c\u8a08\u7b97\u958b\u59cb\u300d\u3092\u30af\u30ea\u30c3\u30af\u3059\u308b\u3068, \u7a4d\u5206 S \u3092\u6c42\u3081\u5404\u884c\u306e 1 \u5217\u76ee\u306b\u51fa\u529b\u3057\u307e\u3059.<\/p>\n

\u4f7f\u7528\u3059\u308b\u30d7\u30ed\u30b0\u30e9\u30e0\u306f, \u7121\u9650\u533a\u9593\u306e\u5834\u5408 Qagi \u304a\u3088\u3073 Deiint \u304b\u3089\u9078\u3076\u3053\u3068\u304c\u3067\u304d\u307e\u3059.<\/p>\n

\u8a08\u7b97\u7cbe\u5ea6\u306e\u6a19\u6e96\u5024\u306f \\(10^{-8}\\) \u3067\u3059. Qagi \u306e EpsAbs \u304a\u3088\u3073 EpsRel \u306b\u3053\u308c\u3092\u8a2d\u5b9a\u3057\u307e\u3059. Deiint \u3067\u306f Eps \u306b\u8a2d\u5b9a\u3057\u307e\u3059.<\/p>\n

\u305d\u308c\u305e\u308c\u306e\u30bb\u30eb\u7bc4\u56f2\u306f\u5fc5\u8981\u306a\u7bc4\u56f2\u3088\u308a\u3082\u5927\u304d\u304f\u6307\u5b9a\u3059\u308b\u3053\u3068\u304c\u3067\u304d, \u305d\u306e\u5834\u5408\u306b\u306f\u5de6\u4e0a\u304b\u3089\u5fc5\u8981\u306a\u3060\u3051\u306e\u5927\u304d\u3055\u306e\u7bc4\u56f2\u3092\u4f7f\u3044\u307e\u3059.<\/p>\n

\"\"<\/p>\n

\u300c\u4fdd\u5b58\uff0f\u8aad\u8fbc\u300d\u306b\u3064\u3044\u3066\u306f\u3053\u3061\u3089<\/a>\u3092\u53c2\u7167\u304f\u3060\u3055\u3044.<\/p>\n

\u300c\u30d8\u30eb\u30d7\u300d\u3092\u30af\u30ea\u30c3\u30af\u3059\u308b\u3068\u30cd\u30c3\u30c8\u63a5\u7d9a\u4e2d\u3067\u3042\u308c\u3070\u3053\u306e\u30da\u30fc\u30b8\u3092\u8868\u793a\u3057\u307e\u3059.<\/p>\n

\u53f3\u4e0a\u306e\u300c\uff1f\u300d\u306f\u6b63\u3057\u304f\u52d5\u4f5c\u3057\u307e\u305b\u3093. \u300c\u30d8\u30eb\u30d7\u300d\u30dc\u30bf\u30f3\u3092\u4f7f\u7528\u3057\u3066\u304f\u3060\u3055\u3044.<\/p>\n","protected":false},"excerpt":{"rendered":"

\u7a4d\u5206\u533a\u9593\u306e\u4e0a\u9650\u4e0b\u9650\u5171\u306b\u7121\u9650\u5927\u3059\u306a\u308f\u3061 [-\u221e, +\u221e] \u306e\u6570\u5024\u7a4d\u5206\u3092\u884c\u3044\u307e\u3059. \\[ f(x) = \\frac{1}{1 + x^2} \\] \u306e\u7a4d\u5206 \\[ S = \\int_{-\\infty}^{+\\infty} f(x […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"_monsterinsights_skip_tracking":false,"footnotes":""},"categories":[14],"tags":[],"class_list":["post-3062","post","type-post","status-publish","format-standard","hentry","category-document"],"aioseo_notices":[],"aioseo_head":"\n\t\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\n\t\t