XLPack 7.0
XLPack Numerical Library (Excel VBA) Reference Manual
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◆ Dptsvx()

Sub Dptsvx ( Fact As  String,
N As  Long,
D() As  Double,
E() As  Double,
Df() As  Double,
Ef() As  Double,
B() As  Double,
X() As  Double,
RCond As  Double,
FErr() As  Double,
BErr() As  Double,
Info As  Long,
Optional Nrhs As  Long = 1 
)

(Expert driver) Solution to system of linear equations AX = B for a symmetric positive definite tridiagonal matrix

Purpose
This routine uses the factorization A = L*D*L^T to compute the solution to a real system of linear equations
A * X = B,
where A is an n x n symmetric positive definite tridiagonal matrix, and X and B are n x nrhs matrices.
Error bounds on the solution and a condition estimate are also provided.
Description
The following steps are performed:

  1. If Fact = "N", the matrix A is factored as
    A = L * D * L^T,
    where L is a unit lower bidiagonal matrix and D is diagonal. The factorization can also be regarded as having the form
    A = U^T * D * U.

  2. If the leading i x i principal minor is not positive definite, then the routine returns with Info = i. Otherwise, the factored form of A is used to estimate the condition number of the matrix A. If the reciprocal of the condition number is less than machine precision, Info = n+1 is returned as a warning, but the routine still goes on to solve for X and compute error bounds as described below.

  3. The system of equations is solved for X using the factored form of A.

  4. Iterative refinement is applied to improve the computed solution matrix and calculate error bounds and backward error estimates for it.
Parameters
[in]FactSpecifies whether or not the factored form of A has been supplied on entry.
= "F": Df() and Ef() contain the factored form of A. Df() and Ef() will not be modified.
= "N": The matrix A will be copied to Df() and Ef() and factored.
[in]NOrder of the matrix A. (N >= 0) (If N = 0, returns without computation)
[in]D()Array D(LD - 1) (LD >= N)
N diagonal elements of the symmetric positive definite tridiagonal matrix A.
[in]E()Array E(LE - 1) (LE >= N - 1)
N-1 sub-diagonal elements of the symmetric positive definite tridiagonal matrix A.
[in,out]Df()Array Df(LDf - 1) (LDf >= N)
[in] If Fact = "F", n diagonal elements of the diagonal matrix D from the L*D*L^T factorization of A, are to be stored.
[out] If Fact = "N", n diagonal elements of the diagonal matrix D from the L*D*L^T factorization of A, are returned.
[in,out]Ef()Array Ef(LEf - 1) (LEf >= N - 1)
[in] If Fact = "F", N-1 sub-diagonal elements of the unit bidiagonal factor L from the L*D*L^T factorization of A, are to be stored.
[out] If Fact = "N", N-1 sub-diagonal elements of the unit bidiagonal factor L from the L*D*L^T factorization of A, are returned.
[in]B()Array B(LB1 - 1, LB2 - 1) (LB1 >= max(1, N), LB2 >= Nrhs) (2D array) or B(LB - 1) (LB >= max(1, N), Nrhs = 1) (1D array)
N x Nrhs right hand side matrix B.
[out]X()Array X(LX1 - 1, LX2 - 1) (LX1 >= max(1, N), LX2 >= Nrhs) (2D array) or X(LX - 1) (LX >= max(1, N), Nrhs = 1) (1D array)
If Info = 0 or Info = N+1, the N x Nrhs solution matrix X.
[out]RCondThe reciprocal condition number of the matrix A. If RCond is less than the machine precision (in particular, if RCond = 0), the matrix is singular to working precision. This condition is indicated by a return code of Info > 0.
[out]FErr()Array FErr(LFErr - 1) (LFErr >= Nrhs)
The forward error bound for each solution vector X(j) (the j-th column of the solution matrix X). If Xtrue is the true solution corresponding to X(j), FErr(j-1) is an estimated upper bound for the magnitude of the largest element in (X(j) - Xtrue) divided by the magnitude of the largest element in X(j).
[out]BErr()Array BErr(LBErr - 1) (LBErr >= Nrhs)
The componentwise relative backward error of each solution vector X(j) (i.e., the smallest relative change in any element of A or B that makes X(j) an exact solution).
[out]Info= 0: Successful exit.
= -1: The argument Fact had an illegal value. (Fact <> "F" nor "N")
= -2: The argument N had an illegal value. (N < 0)
= -3: The argument D() is invalid.
= -4: The argument E() is invalid.
= -5: The argument Df() is invalid.
= -6: The argument Ef() is invalid.
= -7: The argument B() is invalid.
= -8: The argument X() is invalid.
= -10: The argument FErr() is invalid.
= -11: The argument BErr() is invalid.
= -13: The argument Nrhs had an illegal value. (Nrhs < 0)
[in]Nrhs(Optional)
Number of right hand sides, i.e., number of columns of the matrix B. (Nrhs >= 0) (If Nrhs = 0, returns without computation) (default = 1)
Reference
LAPACK
Example Program
Solve the system of linear equations Ax = B and estimate the reciprocal of the condition number (RCond) of A, where A is symmetric positive definite tridiagonal matrix and
( 2.58 -0.99 0 ) ( -1.1850 )
A = ( -0.99 0.69 -0.03 ), B = ( 0.1410 )
( 0 -0.03 0.18 ) ( 0.1614 )
Sub Ex_Dptsvx()
Const N As Long = 3
Dim D(N - 1) As Double, E(N - 2) As Double, B(N - 1) As Double
Dim Df(N - 1) As Double, Ef(N - 2) As Double, X(N - 1) As Double
Dim FErr(0) As Double, BErr(0) As Double
Dim RCond As Double, Info As Long
D(0) = 2.58: D(1) = 0.69: D(2) = 0.18
E(0) = -0.99: E(1) = -0.03
B(0) = -1.185: B(1) = 0.141: B(2) = 0.1614
Call Dptsvx("N", N, D(), E(), Df(), Ef(), B(), X(), RCond, FErr(), BErr(), Info)
Debug.Print "X =", X(0), X(1), X(2)
Debug.Print "RCond =", RCond
Debug.Print "Info =", Info
End Sub
Sub Dptsvx(Fact As String, N As Long, D() As Double, E() As Double, Df() As Double, Ef() As Double, B() As Double, X() As Double, RCond As Double, FErr() As Double, BErr() As Double, Info As Long, Optional Nrhs As Long=1)
(Expert driver) Solution to system of linear equations AX = B for a symmetric positive definite tridi...
Example Results
X = -0.82 -0.94 0.74
RCond = 0.0437508336668
Info = 0