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◆ Zgtsv()
| Sub Zgtsv |
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N As |
Long, |
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Dl() As |
Complex, |
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D() As |
Complex, |
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Du() As |
Complex, |
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B() As |
Complex, |
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Info As |
Long, |
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Optional Nrhs As |
Long = 1 |
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(Simple driver) Solution to system of linear equations AX = B for a complex tridiagonal matrix
- Purpose
- This routine solves the equation where A is an N x N tridiagonal matrix, by Gaussian elimination with partial pivoting.
Note that the equation A^T*X = B may be solved by interchanging the order of the arguments du and dl.
- Parameters
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| [in] | N | Order of the matrix A. (N >= 0) (If N = 0, returns without computation) |
| [in,out] | Dl() | Array Dl(LDl - 1) (LDl >= N - 1)
[in] N-1 sub-diagonal elements of A.
[out] N-2 elements of the second super-diagonal of the upper triangular matrix U from the LU factorization of A, in Dl(0), ..., Dl(N-3). |
| [in,out] | D() | Array D(LD - 1) (LD >= N)
[in] Diagonal elements of A.
[out] Diagonal elements of U. |
| [in,out] | Du() | Array Du(LDu - 1) (LDu >= N - 1)
[in] N-1 super-diagonal elements of A.
[out] N-1 elements of the first super-diagonal of U. |
| [in,out] | B() | Array B(LB1 - 1, LB2 - 1) (LB1 >= max(1, N), LB2 >= Nrhs) (2D array) or B(LB - 1) (LB >= max(1, N), Nrhs = 1) (1D array)
[in] N x Nrhs matrix of right hand side matrix B.
[out] If Info = 0, the N x Nrhs solution matrix X. |
| [out] | Info | = 0: Successful exit.
= -1: The argument N had an illegal value. (N < 0)
= -2: The argument Dl() is invalid.
= -3: The argument D() is invalid.
= -4: The argument Du() is invalid.
= -5: The argument B() is invalid.
= -7: The argument Nrhs had an illegal value. (Nrhs < 0, or, Nrhs <> 1 and B() is 1D array)
= i > 0: The i-th diagonal element of the factor U is exactly zero, and the solution has not been computed. The factorization has not been completed unless i = n. |
| [in] | Nrhs | (Optional)
Number of right hand sides, i.e., number of columns of the matrix B. (Nrhs >= 0) (If Nrhs = 0, returns without computation) (default = 1) |
- Reference
- LAPACK
- Example Program
- Solve the system of linear equations Ax = B and estimate the reciprocal of the condition number (RCond) of A, where
( 0.81+0.37i -0.20-0.11i 0 )
A = ( 0.64+0.51i -0.80-0.92i -0.93-0.32i )
( 0 0.71+0.59i -0.29+0.86i )
( -0.0484+0.2644i )
B = ( -0.2644-1.0228i )
( -0.5299+1.5025i )
Sub Ex_Zgtsv()
Const N = 3
Dim Dl(N - 2) As Complex, D(N - 1) As Complex, Du(N - 2) As Complex
Dim B(N - 1) As Complex, Info As Long
Dl(0) = Cmplx(0.64, 0.51): Dl(1) = Cmplx(0.71, 0.59)
D(0) = Cmplx(0.81, 0.37): D(1) = Cmplx(-0.8, -0.92): D(2) = Cmplx(-0.29, 0.86)
Du(0) = Cmplx(0.2, -0.11): Du(1) = Cmplx(-0.93, -0.32)
B(0) = Cmplx(-0.0484, 0.2644): B(1) = Cmplx(-0.2644, -1.0228): B(2) = Cmplx(-0.5299, 1.5025)
Call Zgtsv(N, Dl(), D(), Du(), B(), Info)
Debug.Print "X =",
Debug.Print "Info =", Info
End Sub
Function Cmplx(R As Double, Optional I As Double=0) As Complex Building complex number
Function Cimag(A As Complex) As Double Imaginary part of complex number
Function Creal(A As Complex) As Double Real part of complex number
Sub Zgtsv(N As Long, Dl() As Complex, D() As Complex, Du() As Complex, B() As Complex, Info As Long, Optional Nrhs As Long=1) (Simple driver) Solution to system of linear equations AX = B for a complex tridiagonal matrix
- Example Results
X = -0.15 0.19 0.2 0.94 0.79 -0.13
Info = 0
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